I'm working on a World 1 TAS right now, but I probably won't do world 2 until I figure out how the hell to beat 2-2. Professional frame-by-frame time wizard. YouTube - Twitter - SMW Glitch List - SMW Randomizer

Well, Geez LeChuck... I figured out the P-Castle and I figured it out the right way. I even figured out the ORIGINAL WAY :-Þ

I don't know what's wrong with these people.

It's really easy.

if X = 1 then

X^2 = 1 as well
X^2 - 1 = 1 - 1 since it's an equation.
(X + 1)(X - 1) = 1 - 1 since X^2 - 1 is the difference of 2 squares, it can be adequately factored.

Therefore you can operate on it like an equation:

(X + 1)(X - 1) /(1 - 1) = (1 - 1)/(1 - 1)

Now if X = 1 then the 2 halfs of the multiplier and the dividend cancel out... Just like how 2 * 5 / 2 = 5. Therefore,

(X + 1)=(1 - 1)/(1 - 1).

Now 1 - 1 is 0, and 0 over anything is 0 weather it's 0 halves, 0 thirds... 0 anything. so...

(X + 1) = 0

And since X = 1, then
2 = 0. Now how many springboards are there? 2! How many do you want to be there? 0! There fore, just simply 8 + 2 = -1, and walk through to the door unobstructed. It's So easy you guys

Come on! I figured that out before anyone, I think...

Well, Geez LeChuck... I figured out the P-Castle and I figured it out the right way. I even figured out the ORIGINAL WAY :-Þ

I don't know what's wrong with these people.

It's really easy.

if X = 1 then

X^2 = 1 as well
X^2 - 1 = 1 - 1 since it's an equation.
(X + 1)(X - 1) = 1 - 1 since X^2 - 1 is the difference of 2 squares, it can be adequately factored.

Therefore you can operate on it like an equation:

(X + 1)(X - 1) /(1 - 1) = (1 - 1)/(1 - 1)

Now if X = 1 then the 2 halfs of the multiplier and the dividend cancel out... Just like how 2 * 5 / 2 = 5. Therefore,

(X + 1)=(1 - 1)/(1 - 1).

Now 1 - 1 is 0, and 0 over anything is 0 weather it's 0 halves, 0 thirds... 0 anything. so...

(X + 1) = 0

And since X = 1, then
2 = 0. Now how many springboards are there? 2! How many do you want to be there? 0! There fore, just simply 8 + 2 = -1, and walk through to the door unobstructed. It's So easy you guys

Come on! I figured that out before anyone, I think...

Well, Geez LeChuck... I figured out the P-Castle and I figured it out the right way. I even figured out the ORIGINAL WAY :-Þ

I don't know what's wrong with these people.

It's really easy.

if X = 1 then

X^2 = 1 as well
X^2 - 1 = 1 - 1 since it's an equation.
(X + 1)(X - 1) = 1 - 1 since X^2 - 1 is the difference of 2 squares, it can be adequately factored.

Therefore you can operate on it like an equation:

(X + 1)(X - 1) /(1 - 1) = (1 - 1)/(1 - 1)

Now if X = 1 then the 2 halfs of the multiplier and the dividend cancel out... Just like how 2 * 5 / 2 = 5. Therefore,

(X + 1)=(1 - 1)/(1 - 1).

Now 1 - 1 is 0, and 0 over anything is 0 weather it's 0 halves, 0 thirds... 0 anything. so...

(X + 1) = 0

And since X = 1, then
2 = 0. Now how many springboards are there? 2! How many do you want to be there? 0! There fore, just simply 8 + 2 = -1, and walk through to the door unobstructed. It's So easy you guys

Come on! I figured that out before anyone, I think...

lolwut

*sigh*

If 2 = 0 then, what happens when you come out of the pipe?

hint: abuse sprite limitations.
you have to double grab 2 p-switches and carry them though the pipe and then go back.
then, go to the right and then to the left so you have processed 8 sprites, so the sprite limitations don't allow the springboard to show up...

eighteencharacters, what was the use of that equation?? O.o

I might put some sort of signature here once. I guess.

eighteencharacters, what was the use of that equation?? O.o

There was no point. Its called stupidity at its finest.

Also, 2≠0, so he failed at math more than he failed at overthinking. Plus, theres only one springboard, so where the hell did he get a second one from? Professional frame-by-frame time wizard. YouTube - Twitter - SMW Glitch List - SMW Randomizer

X^2 = 1 as well
X^2 - 1 = 1 - 1 since it's an equation.
(X + 1)(X - 1) = 1 - 1 since X^2 - 1 is the difference of 2 squares, it can be adequately factored.

Therefore you can operate on it like an equation:

(X + 1)(X - 1) /(1 - 1) = (1 - 1)/(1 - 1)

Now if X = 1 then the 2 halfs of the multiplier and the dividend cancel out... Just like how 2 * 5 / 2 = 5. Therefore,

(X + 1)=(1 - 1)/(1 - 1).

Now 1 - 1 is 0, and 0 over anything is 0 weather it's 0 halves, 0 thirds... 0 anything. so...

(X + 1) = 0

And since X = 1, then
2 = 0. Now how many springboards are there? 2! How many do you want to be there? 0! There fore, just simply 8 + 2 = -1, and walk through to the door unobstructed. It's So easy you guys

That's what I thought, but I didn't think anyone else would get it. It's so simple.

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Warning: Opinions expressed by Lexie or others in this post do not necessarily reflect the views, opinions, or position of Lexie himself on the matter(s) being discussed therein.

Okay, this is getting REALLY, REALLY frustrating. I found out how to keep the springboard in The Muncherrun, but now I can't get enough freaking speed to get the the high jump area!

GOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOD THE MUNCHERRUN CAN GO TO HELL! STUPID TURNBLOCKS AND STUPID TOOLS SCREWING ME OVER!!!!!!!!!!!!!!!!

Nice hack so far. I'm at Fake and I have no idea what to do.. Now it's break time. I tortured myself a lot today beating three levels :S

Also, what a Kaizo-ish feeling on the SPW3 Breakout.. Must have died more than 50 times. Run, Shell Run was mostly trial and error. Taking and leaving the right coins.

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